2x^2+325x-7000=0

Solution for 2x^2+325x-7000=0 equation:

2x^2+325x-7000=0

a = 2; b = 325; c = -7000;
Δ = b2-4ac
Δ = 3252-4·2·(-7000)
Δ = 161625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{161625}=\sqrt{25*6465}=\sqrt{25}*\sqrt{6465}=5\sqrt{6465}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(325)-5\sqrt{6465}}{2*2}=\frac{-325-5\sqrt{6465}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(325)+5\sqrt{6465}}{2*2}=\frac{-325+5\sqrt{6465}}{4}
$